The solubility of nitrogen in water is 8.21 x 10-4 at 0°C when the N2 pressure above water is 0.790 atm.

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The solubility of nitrogen in water is 8.21 x 10-4 at 0°C when the N2 pressure above water is 0.790 atm.

Answer: The solubility of nitrogen in water is 8.21 × 10-4 mol/L at 0°C when the N2 pressure above water is 0.790 atm. Calculate the Henry’s law constant for N2 in units of mol/L · atm for Henry’s law in the form C = kP, where C is the gas concentration in mol/L. Calculate the solubility of N2 in water when the partial pressure of nitrogen above water is 1.10 atm at 0°C.

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